2m^2+10m-28=0

Solution for 2m^2+10m-28=0 equation:

2m^2+10m-28=0

a = 2; b = 10; c = -28;
Δ = b2-4ac
Δ = 102-4·2·(-28)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-18}{2*2}=\frac{-28}{4}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+18}{2*2}=\frac{8}{4}
=2
$